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-.0001x^2+300x+2=0
We add all the numbers together, and all the variables
-0.0001x^2+300x+2=0
a = -0.0001; b = 300; c = +2;
Δ = b2-4ac
Δ = 3002-4·(-0.0001)·2
Δ = 90000.0008
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(300)-\sqrt{90000.0008}}{2*-0.0001}=\frac{-300-\sqrt{90000.0008}}{-0.0002} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(300)+\sqrt{90000.0008}}{2*-0.0001}=\frac{-300+\sqrt{90000.0008}}{-0.0002} $
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